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Metamath Proof Explorer

Theorem 1pneg1e0

Description: 1 + -u 1 is 0. (Contributed by David A. Wheeler, 8-Dec-2018)

Ref Expression
Assertion 1pneg1e0 ( 1 + - 1 ) = 0

Proof

Step Hyp Ref Expression
1 ax-1cn ⊢ 1 ∈ ℂ
2 1 negidi ⊢ ( 1 + - 1 ) = 0