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Metamath Proof Explorer

Theorem 1pneg1e0

Description: 1 + -u 1 is 0. (Contributed by David A. Wheeler, 8-Dec-2018)

		Ref	Expression
	Assertion	1pneg1e0	$⊢ 1 + -1 = 0$

Step	Hyp	Ref	Expression
1		ax-1cn	$⊢ 1 \in ℂ$
2	1	negidi	$⊢ 1 + -1 = 0$