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Metamath Proof Explorer

Theorem exp4a

Description: An exportation inference. (Contributed by NM, 26-Apr-1994) (Proof shortened by Wolf Lammen, 20-Jul-2021)

		Ref	Expression
	Hypothesis	exp4a.1	$⊢ φ \to (ψ \to ((χ \land θ) \to τ))$
	Assertion	exp4a	$⊢ φ \to (ψ \to (χ \to (θ \to τ)))$

Step	Hyp	Ref	Expression
1		exp4a.1	$⊢ φ \to (ψ \to ((χ \land θ) \to τ))$
2	1	imp	$⊢ (φ \land ψ) \to ((χ \land θ) \to τ)$
3	2	exp4b	$⊢ φ \to (ψ \to (χ \to (θ \to τ)))$