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Metamath Proof Explorer

Theorem ensymd

Description: Symmetry of equinumerosity. Deduction form of ensym . (Contributed by David Moews, 1-May-2017)

		Ref	Expression
	Hypothesis	ensymd.1	$⊢ φ \to A \approx B$
	Assertion	ensymd	$⊢ φ \to B \approx A$

Step	Hyp	Ref	Expression
1		ensymd.1	$⊢ φ \to A \approx B$
2		ensym	$⊢ A \approx B \to B \approx A$
3	1 2	syl	$⊢ φ \to B \approx A$