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Metamath Proof Explorer

Theorem animorr

Description: Conjunction implies disjunction with one common formula (2/4). (Contributed by BJ, 4-Oct-2019)

		Ref	Expression
	Assertion	animorr	$⊢ (φ \land ψ) \to (χ \lor ψ)$

Step	Hyp	Ref	Expression
1		simpr	$⊢ (φ \land ψ) \to ψ$
2	1	olcd	$⊢ (φ \land ψ) \to (χ \lor ψ)$