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Description: For each odd nonnegative integer there is a nonnegative integer which, multiplied by 2 and increased by 1, results in the odd nonnegative integer. (Contributed by AV, 30-May-2020) (Revised by AV, 22-Jun-2020)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | nn0onn0exALTV | |- ( ( N e. NN0 /\ N e. Odd ) -> E. m e. NN0 N = ( ( 2 x. m ) + 1 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nn0oALTV | |- ( ( N e. NN0 /\ N e. Odd ) -> ( ( N - 1 ) / 2 ) e. NN0 ) |
|
| 2 | simpr | |- ( ( N e. NN0 /\ ( ( N - 1 ) / 2 ) e. NN0 ) -> ( ( N - 1 ) / 2 ) e. NN0 ) |
|
| 3 | oveq2 | |- ( m = ( ( N - 1 ) / 2 ) -> ( 2 x. m ) = ( 2 x. ( ( N - 1 ) / 2 ) ) ) |
|
| 4 | 3 | oveq1d | |- ( m = ( ( N - 1 ) / 2 ) -> ( ( 2 x. m ) + 1 ) = ( ( 2 x. ( ( N - 1 ) / 2 ) ) + 1 ) ) |
| 5 | 4 | eqeq2d | |- ( m = ( ( N - 1 ) / 2 ) -> ( N = ( ( 2 x. m ) + 1 ) <-> N = ( ( 2 x. ( ( N - 1 ) / 2 ) ) + 1 ) ) ) |
| 6 | 5 | adantl | |- ( ( ( N e. NN0 /\ ( ( N - 1 ) / 2 ) e. NN0 ) /\ m = ( ( N - 1 ) / 2 ) ) -> ( N = ( ( 2 x. m ) + 1 ) <-> N = ( ( 2 x. ( ( N - 1 ) / 2 ) ) + 1 ) ) ) |
| 7 | nn0cn | |- ( N e. NN0 -> N e. CC ) |
|
| 8 | peano2cnm | |- ( N e. CC -> ( N - 1 ) e. CC ) |
|
| 9 | 7 8 | syl | |- ( N e. NN0 -> ( N - 1 ) e. CC ) |
| 10 | 2cnd | |- ( N e. NN0 -> 2 e. CC ) |
|
| 11 | 2ne0 | |- 2 =/= 0 |
|
| 12 | 11 | a1i | |- ( N e. NN0 -> 2 =/= 0 ) |
| 13 | 9 10 12 | divcan2d | |- ( N e. NN0 -> ( 2 x. ( ( N - 1 ) / 2 ) ) = ( N - 1 ) ) |
| 14 | 13 | oveq1d | |- ( N e. NN0 -> ( ( 2 x. ( ( N - 1 ) / 2 ) ) + 1 ) = ( ( N - 1 ) + 1 ) ) |
| 15 | npcan1 | |- ( N e. CC -> ( ( N - 1 ) + 1 ) = N ) |
|
| 16 | 7 15 | syl | |- ( N e. NN0 -> ( ( N - 1 ) + 1 ) = N ) |
| 17 | 14 16 | eqtr2d | |- ( N e. NN0 -> N = ( ( 2 x. ( ( N - 1 ) / 2 ) ) + 1 ) ) |
| 18 | 17 | adantr | |- ( ( N e. NN0 /\ ( ( N - 1 ) / 2 ) e. NN0 ) -> N = ( ( 2 x. ( ( N - 1 ) / 2 ) ) + 1 ) ) |
| 19 | 2 6 18 | rspcedvd | |- ( ( N e. NN0 /\ ( ( N - 1 ) / 2 ) e. NN0 ) -> E. m e. NN0 N = ( ( 2 x. m ) + 1 ) ) |
| 20 | 1 19 | syldan | |- ( ( N e. NN0 /\ N e. Odd ) -> E. m e. NN0 N = ( ( 2 x. m ) + 1 ) ) |