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Metamath Proof Explorer

Theorem oveq1d

Description: Equality deduction for operation value. (Contributed by NM, 13-Mar-1995)

Ref Expression
Hypothesis oveq1d.1 
|- ( ph -> A = B )
Assertion oveq1d 
|- ( ph -> ( A F C ) = ( B F C ) )

Proof

Step Hyp Ref Expression
1 oveq1d.1 
 |-  ( ph -> A = B )
2 oveq1 
 |-  ( A = B -> ( A F C ) = ( B F C ) )
3 1 2 syl 
 |-  ( ph -> ( A F C ) = ( B F C ) )