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Description: Deduce sub-division-ring from field extension. (Contributed by Thierry Arnoux, 26-Oct-2025)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | fldextsdrg.1 | |- B = ( Base ` F ) |
|
| fldextsdrg.2 | |- ( ph -> E /FldExt F ) |
||
| Assertion | fldextsdrg | |- ( ph -> B e. ( SubDRing ` E ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | fldextsdrg.1 | |- B = ( Base ` F ) |
|
| 2 | fldextsdrg.2 | |- ( ph -> E /FldExt F ) |
|
| 3 | fldextfld1 | |- ( E /FldExt F -> E e. Field ) |
|
| 4 | 2 3 | syl | |- ( ph -> E e. Field ) |
| 5 | 4 | flddrngd | |- ( ph -> E e. DivRing ) |
| 6 | 1 | fldextsubrg | |- ( E /FldExt F -> B e. ( SubRing ` E ) ) |
| 7 | 2 6 | syl | |- ( ph -> B e. ( SubRing ` E ) ) |
| 8 | fldextress | |- ( E /FldExt F -> F = ( E |`s ( Base ` F ) ) ) |
|
| 9 | 2 8 | syl | |- ( ph -> F = ( E |`s ( Base ` F ) ) ) |
| 10 | 1 | oveq2i | |- ( E |`s B ) = ( E |`s ( Base ` F ) ) |
| 11 | 9 10 | eqtr4di | |- ( ph -> F = ( E |`s B ) ) |
| 12 | fldextfld2 | |- ( E /FldExt F -> F e. Field ) |
|
| 13 | 2 12 | syl | |- ( ph -> F e. Field ) |
| 14 | 11 13 | eqeltrrd | |- ( ph -> ( E |`s B ) e. Field ) |
| 15 | 14 | flddrngd | |- ( ph -> ( E |`s B ) e. DivRing ) |
| 16 | issdrg | |- ( B e. ( SubDRing ` E ) <-> ( E e. DivRing /\ B e. ( SubRing ` E ) /\ ( E |`s B ) e. DivRing ) ) |
|
| 17 | 5 7 15 16 | syl3anbrc | |- ( ph -> B e. ( SubDRing ` E ) ) |