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Metamath Proof Explorer

Theorem dtru

Description: Given any set (the " y " in the statement), not all sets are equal to it. The same statement without disjoint variable condition is false since it contradicts stdpc6 . The same comments and revision history concerning axiom usage as in exneq apply. See dtruALT and dtruALT2 for alternate proofs avoiding ax-pr . (Contributed by NM, 7-Nov-2006) Extract exneq as an intermediate result. (Revised by BJ, 2-Jan-2025)

		Ref	Expression
	Assertion	dtru	\|- -. A. x x = y

Proof

Step	Hyp	Ref	Expression
1		exneq	\|- E. x -. x = y
2		exnal	\|- ( E. x -. x = y <-> -. A. x x = y )
3	1 2	mpbi	\|- -. A. x x = y