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Description: If two sets have equal nonzero cardinalities, then they are equinumerous. This assertion and carden2b are meant to replace carden in ZF without AC. (Contributed by Mario Carneiro, 9-Jan-2013)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | carden2a | |- ( ( ( card ` A ) = ( card ` B ) /\ ( card ` A ) =/= (/) ) -> A ~~ B ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | df-ne | |- ( ( card ` A ) =/= (/) <-> -. ( card ` A ) = (/) ) |
|
| 2 | ndmfv | |- ( -. B e. dom card -> ( card ` B ) = (/) ) |
|
| 3 | eqeq1 | |- ( ( card ` A ) = ( card ` B ) -> ( ( card ` A ) = (/) <-> ( card ` B ) = (/) ) ) |
|
| 4 | 2 3 | imbitrrid | |- ( ( card ` A ) = ( card ` B ) -> ( -. B e. dom card -> ( card ` A ) = (/) ) ) |
| 5 | 4 | con1d | |- ( ( card ` A ) = ( card ` B ) -> ( -. ( card ` A ) = (/) -> B e. dom card ) ) |
| 6 | 5 | imp | |- ( ( ( card ` A ) = ( card ` B ) /\ -. ( card ` A ) = (/) ) -> B e. dom card ) |
| 7 | cardid2 | |- ( B e. dom card -> ( card ` B ) ~~ B ) |
|
| 8 | 6 7 | syl | |- ( ( ( card ` A ) = ( card ` B ) /\ -. ( card ` A ) = (/) ) -> ( card ` B ) ~~ B ) |
| 9 | breq2 | |- ( ( card ` A ) = ( card ` B ) -> ( A ~~ ( card ` A ) <-> A ~~ ( card ` B ) ) ) |
|
| 10 | entr | |- ( ( A ~~ ( card ` B ) /\ ( card ` B ) ~~ B ) -> A ~~ B ) |
|
| 11 | 10 | ex | |- ( A ~~ ( card ` B ) -> ( ( card ` B ) ~~ B -> A ~~ B ) ) |
| 12 | 9 11 | biimtrdi | |- ( ( card ` A ) = ( card ` B ) -> ( A ~~ ( card ` A ) -> ( ( card ` B ) ~~ B -> A ~~ B ) ) ) |
| 13 | cardid2 | |- ( A e. dom card -> ( card ` A ) ~~ A ) |
|
| 14 | ndmfv | |- ( -. A e. dom card -> ( card ` A ) = (/) ) |
|
| 15 | 13 14 | nsyl4 | |- ( -. ( card ` A ) = (/) -> ( card ` A ) ~~ A ) |
| 16 | 15 | ensymd | |- ( -. ( card ` A ) = (/) -> A ~~ ( card ` A ) ) |
| 17 | 12 16 | impel | |- ( ( ( card ` A ) = ( card ` B ) /\ -. ( card ` A ) = (/) ) -> ( ( card ` B ) ~~ B -> A ~~ B ) ) |
| 18 | 8 17 | mpd | |- ( ( ( card ` A ) = ( card ` B ) /\ -. ( card ` A ) = (/) ) -> A ~~ B ) |
| 19 | 1 18 | sylan2b | |- ( ( ( card ` A ) = ( card ` B ) /\ ( card ` A ) =/= (/) ) -> A ~~ B ) |