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Description: Lemma 2 for wlkiswwlks2 . (Contributed by Alexander van der Vekens, 20-Jul-2018)
| Ref | Expression | ||
|---|---|---|---|
| Hypothesis | wlkiswwlks2lem.f | ⊢ 𝐹 = ( 𝑥 ∈ ( 0 ..^ ( ( ♯ ‘ 𝑃 ) − 1 ) ) ↦ ( ◡ 𝐸 ‘ { ( 𝑃 ‘ 𝑥 ) , ( 𝑃 ‘ ( 𝑥 + 1 ) ) } ) ) | |
| Assertion | wlkiswwlks2lem2 | ⊢ ( ( ( ♯ ‘ 𝑃 ) ∈ ℕ0 ∧ 𝐼 ∈ ( 0 ..^ ( ( ♯ ‘ 𝑃 ) − 1 ) ) ) → ( 𝐹 ‘ 𝐼 ) = ( ◡ 𝐸 ‘ { ( 𝑃 ‘ 𝐼 ) , ( 𝑃 ‘ ( 𝐼 + 1 ) ) } ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | wlkiswwlks2lem.f | ⊢ 𝐹 = ( 𝑥 ∈ ( 0 ..^ ( ( ♯ ‘ 𝑃 ) − 1 ) ) ↦ ( ◡ 𝐸 ‘ { ( 𝑃 ‘ 𝑥 ) , ( 𝑃 ‘ ( 𝑥 + 1 ) ) } ) ) | |
| 2 | fveq2 | ⊢ ( 𝑥 = 𝐼 → ( 𝑃 ‘ 𝑥 ) = ( 𝑃 ‘ 𝐼 ) ) | |
| 3 | fvoveq1 | ⊢ ( 𝑥 = 𝐼 → ( 𝑃 ‘ ( 𝑥 + 1 ) ) = ( 𝑃 ‘ ( 𝐼 + 1 ) ) ) | |
| 4 | 2 3 | preq12d | ⊢ ( 𝑥 = 𝐼 → { ( 𝑃 ‘ 𝑥 ) , ( 𝑃 ‘ ( 𝑥 + 1 ) ) } = { ( 𝑃 ‘ 𝐼 ) , ( 𝑃 ‘ ( 𝐼 + 1 ) ) } ) |
| 5 | 4 | fveq2d | ⊢ ( 𝑥 = 𝐼 → ( ◡ 𝐸 ‘ { ( 𝑃 ‘ 𝑥 ) , ( 𝑃 ‘ ( 𝑥 + 1 ) ) } ) = ( ◡ 𝐸 ‘ { ( 𝑃 ‘ 𝐼 ) , ( 𝑃 ‘ ( 𝐼 + 1 ) ) } ) ) |
| 6 | simpr | ⊢ ( ( ( ♯ ‘ 𝑃 ) ∈ ℕ0 ∧ 𝐼 ∈ ( 0 ..^ ( ( ♯ ‘ 𝑃 ) − 1 ) ) ) → 𝐼 ∈ ( 0 ..^ ( ( ♯ ‘ 𝑃 ) − 1 ) ) ) | |
| 7 | fvexd | ⊢ ( ( ( ♯ ‘ 𝑃 ) ∈ ℕ0 ∧ 𝐼 ∈ ( 0 ..^ ( ( ♯ ‘ 𝑃 ) − 1 ) ) ) → ( ◡ 𝐸 ‘ { ( 𝑃 ‘ 𝐼 ) , ( 𝑃 ‘ ( 𝐼 + 1 ) ) } ) ∈ V ) | |
| 8 | 1 5 6 7 | fvmptd3 | ⊢ ( ( ( ♯ ‘ 𝑃 ) ∈ ℕ0 ∧ 𝐼 ∈ ( 0 ..^ ( ( ♯ ‘ 𝑃 ) − 1 ) ) ) → ( 𝐹 ‘ 𝐼 ) = ( ◡ 𝐸 ‘ { ( 𝑃 ‘ 𝐼 ) , ( 𝑃 ‘ ( 𝐼 + 1 ) ) } ) ) |