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Description: Only the universal class has the universal class as a subclass. (Contributed by NM, 17-Sep-2003) (Proof shortened by Andrew Salmon, 26-Jun-2011)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | vss | ⊢ ( V ⊆ 𝐴 ↔ 𝐴 = V ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ssv | ⊢ 𝐴 ⊆ V | |
| 2 | 1 | biantrur | ⊢ ( V ⊆ 𝐴 ↔ ( 𝐴 ⊆ V ∧ V ⊆ 𝐴 ) ) |
| 3 | eqss | ⊢ ( 𝐴 = V ↔ ( 𝐴 ⊆ V ∧ V ⊆ 𝐴 ) ) | |
| 4 | 2 3 | bitr4i | ⊢ ( V ⊆ 𝐴 ↔ 𝐴 = V ) |