This is an inofficial mirror of http://metamath.tirix.org for personal testing of a visualizer extension only.

Metamath Proof Explorer

Theorem rspcv

Description: Restricted specialization, using implicit substitution. (Contributed by NM, 26-May-1998) Drop ax-10 , ax-11 , ax-12 . (Revised by SN, 12-Dec-2023)

		Ref	Expression
	Hypothesis	rspcv.1	⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
	Assertion	rspcv	⊢ ( 𝐴 ∈ 𝐵 → ( ∀ 𝑥 ∈ 𝐵 𝜑 → 𝜓 ) )

Proof

Step	Hyp	Ref	Expression
1		rspcv.1	⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
2		id	⊢ ( 𝐴 ∈ 𝐵 → 𝐴 ∈ 𝐵 )
3	1	adantl	⊢ ( ( 𝐴 ∈ 𝐵 ∧ 𝑥 = 𝐴 ) → ( 𝜑 ↔ 𝜓 ) )
4	2 3	rspcdv	⊢ ( 𝐴 ∈ 𝐵 → ( ∀ 𝑥 ∈ 𝐵 𝜑 → 𝜓 ) )