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Metamath Proof Explorer

Theorem raleqbi1dv

Description: Equality deduction for restricted universal quantifier. (Contributed by NM, 16-Nov-1995) (Proof shortened by Steven Nguyen, 5-May-2023)

		Ref	Expression
	Hypothesis	raleqbi1dv.1	⊢ ( 𝐴 = 𝐵 → ( 𝜑 ↔ 𝜓 ) )
	Assertion	raleqbi1dv	⊢ ( 𝐴 = 𝐵 → ( ∀ 𝑥 ∈ 𝐴 𝜑 ↔ ∀ 𝑥 ∈ 𝐵 𝜓 ) )

Proof

Step	Hyp	Ref	Expression
1		raleqbi1dv.1	⊢ ( 𝐴 = 𝐵 → ( 𝜑 ↔ 𝜓 ) )
2		id	⊢ ( 𝐴 = 𝐵 → 𝐴 = 𝐵 )
3	2 1	raleqbidvv	⊢ ( 𝐴 = 𝐵 → ( ∀ 𝑥 ∈ 𝐴 𝜑 ↔ ∀ 𝑥 ∈ 𝐵 𝜓 ) )