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Metamath Proof Explorer

Theorem pncan3d

Description: Subtraction and addition of equals. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses negidd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
pncand.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
Assertion pncan3d ( 𝜑 → ( 𝐴 + ( 𝐵 − 𝐴 ) ) = 𝐵 )

Proof

Step Hyp Ref Expression
1 negidd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 pncand.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
3 pncan3 ⊢ ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ) → ( 𝐴 + ( 𝐵 − 𝐴 ) ) = 𝐵 )
4 1 2 3 syl2anc ⊢ ( 𝜑 → ( 𝐴 + ( 𝐵 − 𝐴 ) ) = 𝐵 )