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Metamath Proof Explorer
Description: Deduction form of pm2.24 . (Contributed by NM, 30-Jan-2006)
|
|
Ref |
Expression |
|
Hypothesis |
pm2.24d.1 |
⊢ ( 𝜑 → 𝜓 ) |
|
Assertion |
pm2.24d |
⊢ ( 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
pm2.24d.1 |
⊢ ( 𝜑 → 𝜓 ) |
| 2 |
1
|
a1d |
⊢ ( 𝜑 → ( ¬ 𝜒 → 𝜓 ) ) |
| 3 |
2
|
con1d |
⊢ ( 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |