This is an inofficial mirror of http://metamath.tirix.org for personal testing of a visualizer extension only.

Metamath Proof Explorer

Theorem nfsbv

Description: If z is not free in ph , then it is not free in [ y / x ] ph when z is disjoint from both x and y . Version of nfsb with an additional disjoint variable condition on x , z but not requiring ax-13 . (Contributed by Mario Carneiro, 11-Aug-2016) (Revised by Wolf Lammen, 7-Feb-2023) Remove disjoint variable condition on x , y . (Revised by Steven Nguyen, 13-Aug-2023) (Proof shortened by Wolf Lammen, 25-Oct-2024)

		Ref	Expression
	Hypothesis	nfsbv.nf	⊢ Ⅎ 𝑧 𝜑
	Assertion	nfsbv	⊢ Ⅎ 𝑧 [ 𝑦 / 𝑥 ] 𝜑

Proof

Step	Hyp	Ref	Expression
1		nfsbv.nf	⊢ Ⅎ 𝑧 𝜑
2	1	nf5ri	⊢ ( 𝜑 → ∀ 𝑧 𝜑 )
3	2	hbsbw	⊢ ( [ 𝑦 / 𝑥 ] 𝜑 → ∀ 𝑧 [ 𝑦 / 𝑥 ] 𝜑 )
4	3	nf5i	⊢ Ⅎ 𝑧 [ 𝑦 / 𝑥 ] 𝜑