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Description: Detach a conjunction of truths in a biconditional. (Contributed by NM, 6-Nov-2011) (Proof shortened by Wolf Lammen, 24-Nov-2012)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | mpbir2and.1 | ⊢ ( 𝜑 → 𝜒 ) | |
| mpbir2and.2 | ⊢ ( 𝜑 → 𝜃 ) | ||
| mpbir2and.3 | ⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜒 ∧ 𝜃 ) ) ) | ||
| Assertion | mpbir2and | ⊢ ( 𝜑 → 𝜓 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | mpbir2and.1 | ⊢ ( 𝜑 → 𝜒 ) | |
| 2 | mpbir2and.2 | ⊢ ( 𝜑 → 𝜃 ) | |
| 3 | mpbir2and.3 | ⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜒 ∧ 𝜃 ) ) ) | |
| 4 | 1 2 | jca | ⊢ ( 𝜑 → ( 𝜒 ∧ 𝜃 ) ) |
| 5 | 4 3 | mpbird | ⊢ ( 𝜑 → 𝜓 ) |