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Metamath Proof Explorer

Theorem metflem

Description: Lemma for metf and others. (Contributed by NM, 30-Aug-2006) (Revised by Mario Carneiro, 14-Aug-2015)

Ref Expression
Assertion metflem ( 𝐷 ∈ ( Met ‘ 𝑋 ) → ( 𝐷 : ( 𝑋 × 𝑋 ) ⟶ ℝ ∧ ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑋 ( ( ( 𝑥 𝐷 𝑦 ) = 0 ↔ 𝑥 = 𝑦 ) ∧ ∀ 𝑧 ∈ 𝑋 ( 𝑥 𝐷 𝑦 ) ≤ ( ( 𝑧 𝐷 𝑥 ) + ( 𝑧 𝐷 𝑦 ) ) ) ) )

Proof

Step Hyp Ref Expression
1 elfvdm ⊢ ( 𝐷 ∈ ( Met ‘ 𝑋 ) → 𝑋 ∈ dom Met )
2 ismet ⊢ ( 𝑋 ∈ dom Met → ( 𝐷 ∈ ( Met ‘ 𝑋 ) ↔ ( 𝐷 : ( 𝑋 × 𝑋 ) ⟶ ℝ ∧ ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑋 ( ( ( 𝑥 𝐷 𝑦 ) = 0 ↔ 𝑥 = 𝑦 ) ∧ ∀ 𝑧 ∈ 𝑋 ( 𝑥 𝐷 𝑦 ) ≤ ( ( 𝑧 𝐷 𝑥 ) + ( 𝑧 𝐷 𝑦 ) ) ) ) ) )
3 1 2 syl ⊢ ( 𝐷 ∈ ( Met ‘ 𝑋 ) → ( 𝐷 ∈ ( Met ‘ 𝑋 ) ↔ ( 𝐷 : ( 𝑋 × 𝑋 ) ⟶ ℝ ∧ ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑋 ( ( ( 𝑥 𝐷 𝑦 ) = 0 ↔ 𝑥 = 𝑦 ) ∧ ∀ 𝑧 ∈ 𝑋 ( 𝑥 𝐷 𝑦 ) ≤ ( ( 𝑧 𝐷 𝑥 ) + ( 𝑧 𝐷 𝑦 ) ) ) ) ) )
4 3 ibi ⊢ ( 𝐷 ∈ ( Met ‘ 𝑋 ) → ( 𝐷 : ( 𝑋 × 𝑋 ) ⟶ ℝ ∧ ∀ 𝑥 ∈ 𝑋 ∀ 𝑦 ∈ 𝑋 ( ( ( 𝑥 𝐷 𝑦 ) = 0 ↔ 𝑥 = 𝑦 ) ∧ ∀ 𝑧 ∈ 𝑋 ( 𝑥 𝐷 𝑦 ) ≤ ( ( 𝑧 𝐷 𝑥 ) + ( 𝑧 𝐷 𝑦 ) ) ) ) )