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Description: Part of proof of Lemma E in Crawley p. 113. TODO: FIX COMMENT. (Contributed by NM, 10-Mar-2013)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | cdleme35.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| cdleme35.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| cdleme35.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | ||
| cdleme35.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| cdleme35.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | ||
| cdleme35.u | ⊢ 𝑈 = ( ( 𝑃 ∨ 𝑄 ) ∧ 𝑊 ) | ||
| cdleme35.f | ⊢ 𝐹 = ( ( 𝑅 ∨ 𝑈 ) ∧ ( 𝑄 ∨ ( ( 𝑃 ∨ 𝑅 ) ∧ 𝑊 ) ) ) | ||
| Assertion | cdleme35g | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( 𝑃 ≠ 𝑄 ∧ ( 𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊 ) ) ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) → ( ( 𝐹 ∨ 𝑈 ) ∧ ( 𝑃 ∨ ( ( 𝑄 ∨ 𝐹 ) ∧ 𝑊 ) ) ) = 𝑅 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cdleme35.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 2 | cdleme35.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 3 | cdleme35.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | |
| 4 | cdleme35.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 5 | cdleme35.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | |
| 6 | cdleme35.u | ⊢ 𝑈 = ( ( 𝑃 ∨ 𝑄 ) ∧ 𝑊 ) | |
| 7 | cdleme35.f | ⊢ 𝐹 = ( ( 𝑅 ∨ 𝑈 ) ∧ ( 𝑄 ∨ ( ( 𝑃 ∨ 𝑅 ) ∧ 𝑊 ) ) ) | |
| 8 | 1 2 3 4 5 6 7 | cdleme35a | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( 𝑃 ≠ 𝑄 ∧ ( 𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊 ) ) ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) → ( 𝐹 ∨ 𝑈 ) = ( 𝑅 ∨ 𝑈 ) ) |
| 9 | 1 2 3 4 5 6 7 | cdleme35e | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( 𝑃 ≠ 𝑄 ∧ ( 𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊 ) ) ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) → ( 𝑃 ∨ ( ( 𝑄 ∨ 𝐹 ) ∧ 𝑊 ) ) = ( 𝑃 ∨ 𝑅 ) ) |
| 10 | 8 9 | oveq12d | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( 𝑃 ≠ 𝑄 ∧ ( 𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊 ) ) ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) → ( ( 𝐹 ∨ 𝑈 ) ∧ ( 𝑃 ∨ ( ( 𝑄 ∨ 𝐹 ) ∧ 𝑊 ) ) ) = ( ( 𝑅 ∨ 𝑈 ) ∧ ( 𝑃 ∨ 𝑅 ) ) ) |
| 11 | 1 2 3 4 5 6 7 | cdleme35f | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( 𝑃 ≠ 𝑄 ∧ ( 𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊 ) ) ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) → ( ( 𝑅 ∨ 𝑈 ) ∧ ( 𝑃 ∨ 𝑅 ) ) = 𝑅 ) |
| 12 | 10 11 | eqtrd | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( 𝑃 ≠ 𝑄 ∧ ( 𝑅 ∈ 𝐴 ∧ ¬ 𝑅 ≤ 𝑊 ) ) ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) → ( ( 𝐹 ∨ 𝑈 ) ∧ ( 𝑃 ∨ ( ( 𝑄 ∨ 𝐹 ) ∧ 𝑊 ) ) ) = 𝑅 ) |