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Description: Part of proof of Lemma E in Crawley p. 113, 3rd paragraph on p. 114, Eq. (1). F and G represent f(s) and f(t) respectively. We show, in their notation, (s \/ t) /\ w=(f(s) \/ f(t)) /\ w. (Contributed by NM, 11-Oct-2012)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | cdleme12.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| cdleme12.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| cdleme12.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | ||
| cdleme12.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| cdleme12.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | ||
| cdleme12.u | ⊢ 𝑈 = ( ( 𝑃 ∨ 𝑄 ) ∧ 𝑊 ) | ||
| cdleme12.f | ⊢ 𝐹 = ( ( 𝑆 ∨ 𝑈 ) ∧ ( 𝑄 ∨ ( ( 𝑃 ∨ 𝑆 ) ∧ 𝑊 ) ) ) | ||
| cdleme12.g | ⊢ 𝐺 = ( ( 𝑇 ∨ 𝑈 ) ∧ ( 𝑄 ∨ ( ( 𝑃 ∨ 𝑇 ) ∧ 𝑊 ) ) ) | ||
| Assertion | cdleme16g | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ∧ ( 𝑇 ∈ 𝐴 ∧ ¬ 𝑇 ≤ 𝑊 ) ∧ ( 𝑃 ≠ 𝑄 ∧ 𝑆 ≠ 𝑇 ) ) ∧ ( ¬ 𝑆 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝑇 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝑈 ≤ ( 𝑆 ∨ 𝑇 ) ) ) → ( ( 𝑆 ∨ 𝑇 ) ∧ 𝑊 ) = ( ( 𝐹 ∨ 𝐺 ) ∧ 𝑊 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cdleme12.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 2 | cdleme12.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 3 | cdleme12.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | |
| 4 | cdleme12.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 5 | cdleme12.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | |
| 6 | cdleme12.u | ⊢ 𝑈 = ( ( 𝑃 ∨ 𝑄 ) ∧ 𝑊 ) | |
| 7 | cdleme12.f | ⊢ 𝐹 = ( ( 𝑆 ∨ 𝑈 ) ∧ ( 𝑄 ∨ ( ( 𝑃 ∨ 𝑆 ) ∧ 𝑊 ) ) ) | |
| 8 | cdleme12.g | ⊢ 𝐺 = ( ( 𝑇 ∨ 𝑈 ) ∧ ( 𝑄 ∨ ( ( 𝑃 ∨ 𝑇 ) ∧ 𝑊 ) ) ) | |
| 9 | 1 2 3 4 5 6 7 8 | cdleme16e | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ∧ ( 𝑇 ∈ 𝐴 ∧ ¬ 𝑇 ≤ 𝑊 ) ∧ ( 𝑃 ≠ 𝑄 ∧ 𝑆 ≠ 𝑇 ) ) ∧ ( ¬ 𝑆 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝑇 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝑈 ≤ ( 𝑆 ∨ 𝑇 ) ) ) → ( ( 𝑆 ∨ 𝑇 ) ∧ ( 𝐹 ∨ 𝐺 ) ) = ( ( 𝑆 ∨ 𝑇 ) ∧ 𝑊 ) ) |
| 10 | 1 2 3 4 5 6 7 8 | cdleme16f | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ∧ ( 𝑇 ∈ 𝐴 ∧ ¬ 𝑇 ≤ 𝑊 ) ∧ ( 𝑃 ≠ 𝑄 ∧ 𝑆 ≠ 𝑇 ) ) ∧ ( ¬ 𝑆 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝑇 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝑈 ≤ ( 𝑆 ∨ 𝑇 ) ) ) → ( ( 𝑆 ∨ 𝑇 ) ∧ ( 𝐹 ∨ 𝐺 ) ) = ( ( 𝐹 ∨ 𝐺 ) ∧ 𝑊 ) ) |
| 11 | 9 10 | eqtr3d | ⊢ ( ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ∧ ( 𝑄 ∈ 𝐴 ∧ ¬ 𝑄 ≤ 𝑊 ) ) ∧ ( ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ∧ ( 𝑇 ∈ 𝐴 ∧ ¬ 𝑇 ≤ 𝑊 ) ∧ ( 𝑃 ≠ 𝑄 ∧ 𝑆 ≠ 𝑇 ) ) ∧ ( ¬ 𝑆 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝑇 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝑈 ≤ ( 𝑆 ∨ 𝑇 ) ) ) → ( ( 𝑆 ∨ 𝑇 ) ∧ 𝑊 ) = ( ( 𝐹 ∨ 𝐺 ) ∧ 𝑊 ) ) |