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Description: A lemma for substitutions, proved from Tarski's FOL. The version without DV ( x , y ) is true but requires ax-13 . The disjoint variable condition DV ( x , ph ) is necessary for both directions: consider substituting x = z for ph . (Contributed by BJ, 25-May-2021)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | bj-eqs | ⊢ ( 𝜑 ↔ ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ax-1 | ⊢ ( 𝜑 → ( 𝑥 = 𝑦 → 𝜑 ) ) | |
| 2 | 1 | alrimiv | ⊢ ( 𝜑 → ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) ) |
| 3 | exim | ⊢ ( ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) → ( ∃ 𝑥 𝑥 = 𝑦 → ∃ 𝑥 𝜑 ) ) | |
| 4 | ax6ev | ⊢ ∃ 𝑥 𝑥 = 𝑦 | |
| 5 | pm2.27 | ⊢ ( ∃ 𝑥 𝑥 = 𝑦 → ( ( ∃ 𝑥 𝑥 = 𝑦 → ∃ 𝑥 𝜑 ) → ∃ 𝑥 𝜑 ) ) | |
| 6 | 4 5 | ax-mp | ⊢ ( ( ∃ 𝑥 𝑥 = 𝑦 → ∃ 𝑥 𝜑 ) → ∃ 𝑥 𝜑 ) |
| 7 | ax5e | ⊢ ( ∃ 𝑥 𝜑 → 𝜑 ) | |
| 8 | 3 6 7 | 3syl | ⊢ ( ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) → 𝜑 ) |
| 9 | 2 8 | impbii | ⊢ ( 𝜑 ↔ ∀ 𝑥 ( 𝑥 = 𝑦 → 𝜑 ) ) |