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Metamath Proof Explorer

Theorem 6lt7

Description: 6 is less than 7. (Contributed by Mario Carneiro, 15-Sep-2013)

		Ref	Expression
	Assertion	6lt7	⊢ 6 < 7

Step	Hyp	Ref	Expression
1		6re	⊢ 6 ∈ ℝ
2	1	ltp1i	⊢ 6 < ( 6 + 1 )
3		df-7	⊢ 7 = ( 6 + 1 )
4	2 3	breqtrri	⊢ 6 < 7