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Description: Obsolete version of 3jaob as of 29-Jun-2025. (Contributed by NM, 13-Sep-2011) (Proof modification is discouraged.) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | 3jaobOLD | ⊢ ( ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 ) ↔ ( ( 𝜑 → 𝜓 ) ∧ ( 𝜒 → 𝜓 ) ∧ ( 𝜃 → 𝜓 ) ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | 3mix1 | ⊢ ( 𝜑 → ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) ) | |
| 2 | 1 | imim1i | ⊢ ( ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 ) → ( 𝜑 → 𝜓 ) ) |
| 3 | 3mix2 | ⊢ ( 𝜒 → ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) ) | |
| 4 | 3 | imim1i | ⊢ ( ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 ) → ( 𝜒 → 𝜓 ) ) |
| 5 | 3mix3 | ⊢ ( 𝜃 → ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) ) | |
| 6 | 5 | imim1i | ⊢ ( ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 ) → ( 𝜃 → 𝜓 ) ) |
| 7 | 2 4 6 | 3jca | ⊢ ( ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 ) → ( ( 𝜑 → 𝜓 ) ∧ ( 𝜒 → 𝜓 ) ∧ ( 𝜃 → 𝜓 ) ) ) |
| 8 | 3jao | ⊢ ( ( ( 𝜑 → 𝜓 ) ∧ ( 𝜒 → 𝜓 ) ∧ ( 𝜃 → 𝜓 ) ) → ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 ) ) | |
| 9 | 7 8 | impbii | ⊢ ( ( ( 𝜑 ∨ 𝜒 ∨ 𝜃 ) → 𝜓 ) ↔ ( ( 𝜑 → 𝜓 ) ∧ ( 𝜒 → 𝜓 ) ∧ ( 𝜃 → 𝜓 ) ) ) |