This is an inofficial mirror of http://metamath.tirix.org for personal testing of a visualizer extension only.
Description: Two different intersecting lines (expressed in terms of atoms) meet at their common point (atom). (Contributed by NM, 2-May-2013) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | 2llnm.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 2llnm.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| 2llnm.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | ||
| 2llnm.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| Assertion | 2llnma2rN | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → ( ( 𝑃 ∨ 𝑅 ) ∧ ( 𝑄 ∨ 𝑅 ) ) = 𝑅 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | 2llnm.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 2 | 2llnm.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 3 | 2llnm.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | |
| 4 | 2llnm.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 5 | simp1 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → 𝐾 ∈ HL ) | |
| 6 | simp21 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → 𝑃 ∈ 𝐴 ) | |
| 7 | simp23 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → 𝑅 ∈ 𝐴 ) | |
| 8 | 2 4 | hlatjcom | ⊢ ( ( 𝐾 ∈ HL ∧ 𝑃 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) → ( 𝑃 ∨ 𝑅 ) = ( 𝑅 ∨ 𝑃 ) ) |
| 9 | 5 6 7 8 | syl3anc | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → ( 𝑃 ∨ 𝑅 ) = ( 𝑅 ∨ 𝑃 ) ) |
| 10 | simp22 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → 𝑄 ∈ 𝐴 ) | |
| 11 | 2 4 | hlatjcom | ⊢ ( ( 𝐾 ∈ HL ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) → ( 𝑄 ∨ 𝑅 ) = ( 𝑅 ∨ 𝑄 ) ) |
| 12 | 5 10 7 11 | syl3anc | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → ( 𝑄 ∨ 𝑅 ) = ( 𝑅 ∨ 𝑄 ) ) |
| 13 | 9 12 | oveq12d | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → ( ( 𝑃 ∨ 𝑅 ) ∧ ( 𝑄 ∨ 𝑅 ) ) = ( ( 𝑅 ∨ 𝑃 ) ∧ ( 𝑅 ∨ 𝑄 ) ) ) |
| 14 | 1 2 3 4 | 2llnma2 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → ( ( 𝑅 ∨ 𝑃 ) ∧ ( 𝑅 ∨ 𝑄 ) ) = 𝑅 ) |
| 15 | 13 14 | eqtrd | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑃 ≠ 𝑄 ∧ ¬ 𝑅 ≤ ( 𝑃 ∨ 𝑄 ) ) ) → ( ( 𝑃 ∨ 𝑅 ) ∧ ( 𝑄 ∨ 𝑅 ) ) = 𝑅 ) |