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Metamath Proof Explorer

Theorem sylgt

Description: Closed form of sylg . (Contributed by BJ, 2-May-2019)

		Ref	Expression
	Assertion	sylgt	$⊢ \forall x (ψ \to χ) \to ((φ \to \forall x ψ) \to (φ \to \forall x χ))$

Step	Hyp	Ref	Expression
1		alim	$⊢ \forall x (ψ \to χ) \to (\forall x ψ \to \forall x χ)$
2	1	imim2d	$⊢ \forall x (ψ \to χ) \to ((φ \to \forall x ψ) \to (φ \to \forall x χ))$