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Metamath Proof Explorer

Theorem simplld

Description: Deduction form of simpll , eliminating a double conjunct. (Contributed by Glauco Siliprandi, 11-Dec-2019)

		Ref	Expression
	Hypothesis	simplld.1	$⊢ φ \to ((ψ \land χ) \land θ)$
	Assertion	simplld	$⊢ φ \to ψ$

Step	Hyp	Ref	Expression
1		simplld.1	$⊢ φ \to ((ψ \land χ) \land θ)$
2	1	simpld	$⊢ φ \to (ψ \land χ)$
3	2	simpld	$⊢ φ \to ψ$