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CLASSICAL FIRST-ORDER LOGIC WITH EQUALITY
Predicate calculus with equality: Tarski's system S2 (1 rule, 6 schemes)
Define proper substitution
sbequ
Metamath Proof Explorer
Description: Equality property for substitution, from Tarski's system. Used in proof
of Theorem 9.7 in Megill p. 449 (p. 16 of the preprint). (Contributed by NM , 14-May-1993) Revise df-sb . (Revised by BJ , 30-Dec-2020)
Ref
Expression
Assertion
sbequ
⊢ x = y → x z φ ↔ y z φ
Proof
Step
Hyp
Ref
Expression
1
equequ2
⊢ x = y → u = x ↔ u = y
2
1
imbi1d
⊢ x = y → u = x → ∀ z z = u → φ ↔ u = y → ∀ z z = u → φ
3
2
albidv
⊢ x = y → ∀ u u = x → ∀ z z = u → φ ↔ ∀ u u = y → ∀ z z = u → φ
4
dfsb
⊢ x z φ ↔ ∀ u u = x → ∀ z z = u → φ
5
dfsb
⊢ y z φ ↔ ∀ u u = y → ∀ z z = u → φ
6
3 4 5
3bitr4g
⊢ x = y → x z φ ↔ y z φ