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Metamath Proof Explorer

Theorem rnssi

Description: Subclass inference for range. (Contributed by Peter Mazsa, 24-Sep-2022)

		Ref	Expression
	Hypothesis	rnssi.1	$⊢ A \subseteq B$
	Assertion	rnssi	$⊢ ran A \subseteq ran B$

Step	Hyp	Ref	Expression
1		rnssi.1	$⊢ A \subseteq B$
2		rnss	$⊢ A \subseteq B \to ran A \subseteq ran B$
3	1 2	ax-mp	$⊢ ran A \subseteq ran B$