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Metamath Proof Explorer


Theorem reseq2d

Description: Equality deduction for restrictions. (Contributed by Paul Chapman, 22-Jun-2011)

Ref Expression
Hypothesis reseqd.1 φ A = B
Assertion reseq2d φ C A = C B

Proof

Step Hyp Ref Expression
1 reseqd.1 φ A = B
2 reseq2 A = B C A = C B
3 1 2 syl φ C A = C B