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Metamath Proof Explorer

Theorem recseq

Description: Equality theorem for recs . (Contributed by Stefan O'Rear, 18-Jan-2015)

		Ref	Expression
	Assertion	recseq	$⊢ F = G \to recs (F) = recs (G)$

Step	Hyp	Ref	Expression
1		wrecseq3	$⊢ F = G \to wrecs (E, On, F) = wrecs (E, On, G)$
2		df-recs	$⊢ recs (F) = wrecs (E, On, F)$
3		df-recs	$⊢ recs (G) = wrecs (E, On, G)$
4	1 2 3	3eqtr4g	$⊢ F = G \to recs (F) = recs (G)$