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Metamath Proof Explorer

Theorem qseq2d

Description: Equality theorem for quotient set, deduction form. (Contributed by Peter Mazsa, 27-May-2021)

		Ref	Expression
	Hypothesis	qseq1d.1	$⊢ φ \to A = B$
	Assertion	qseq2d	$⊢ φ \to C / A = C / B$

Step	Hyp	Ref	Expression
1		qseq1d.1	$⊢ φ \to A = B$
2		qseq2	$⊢ A = B \to C / A = C / B$
3	1 2	syl	$⊢ φ \to C / A = C / B$