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Metamath Proof Explorer

Theorem pweqd

Description: Equality deduction for power class. (Contributed by NM, 27-Nov-2013)

		Ref	Expression
	Hypothesis	pweqd.1	$⊢ φ \to A = B$
	Assertion	pweqd	$⊢ φ \to 𝒫 A = 𝒫 B$

Step	Hyp	Ref	Expression
1		pweqd.1	$⊢ φ \to A = B$
2		pweq	$⊢ A = B \to 𝒫 A = 𝒫 B$
3	1 2	syl	$⊢ φ \to 𝒫 A = 𝒫 B$