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Metamath Proof Explorer

Theorem orcomd

Description: Commutation of disjuncts in consequent. (Contributed by NM, 2-Dec-2010)

Ref Expression
Hypothesis orcomd.1 ⊢ φ → ψ ∨ χ
Assertion orcomd ⊢ φ → χ ∨ ψ

Proof

Step Hyp Ref Expression
1 orcomd.1 ⊢ φ → ψ ∨ χ
2 orcom ⊢ ψ ∨ χ ↔ χ ∨ ψ
3 1 2 sylib ⊢ φ → χ ∨ ψ