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Metamath Proof Explorer

Theorem lsw0g

Description: The last symbol of an empty word does not exist. (Contributed by Alexander van der Vekens, 11-Nov-2018)

		Ref	Expression
	Assertion	lsw0g	$⊢ lastS (\emptyset) = \emptyset$

Step	Hyp	Ref	Expression
1		wrd0	$⊢ \emptyset \in Word V$
2		hash0	$⊢ \|\emptyset\| = 0$
3		lsw0	$⊢ (\emptyset \in Word V \land \|\emptyset\| = 0) \to lastS (\emptyset) = \emptyset$
4	1 2 3	mp2an	$⊢ lastS (\emptyset) = \emptyset$