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Metamath Proof Explorer


Theorem in31

Description: A rearrangement of intersection. (Contributed by NM, 27-Aug-2012)

Ref Expression
Assertion in31 A B C = C B A

Proof

Step Hyp Ref Expression
1 in12 C A B = A C B
2 incom A B C = C A B
3 incom C B A = A C B
4 1 2 3 3eqtr4i A B C = C B A