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Metamath Proof Explorer

Theorem fveq2d

Description: Equality deduction for function value. (Contributed by NM, 29-May-1999)

		Ref	Expression
	Hypothesis	fveq2d.1	$⊢ φ \to A = B$
	Assertion	fveq2d	$⊢ φ \to F (A) = F (B)$

Step	Hyp	Ref	Expression
1		fveq2d.1	$⊢ φ \to A = B$
2		fveq2	$⊢ A = B \to F (A) = F (B)$
3	1 2	syl	$⊢ φ \to F (A) = F (B)$