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Metamath Proof Explorer

Theorem fveq1i

Description: Equality inference for function value. (Contributed by NM, 2-Sep-2003)

Ref Expression
Hypothesis fveq1i.1 ⊢ F = G
Assertion fveq1i ⊢ F ⁡ A = G ⁡ A

Proof

Step Hyp Ref Expression
1 fveq1i.1 ⊢ F = G
2 fveq1 ⊢ F = G → F ⁡ A = G ⁡ A
3 1 2 ax-mp ⊢ F ⁡ A = G ⁡ A