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Metamath Proof Explorer

Theorem expimpd

Description: Exportation followed by a deduction version of importation. (Contributed by NM, 6-Sep-2008)

		Ref	Expression
	Hypothesis	expimpd.1	$⊢ (φ \land ψ) \to (χ \to θ)$
	Assertion	expimpd	$⊢ φ \to ((ψ \land χ) \to θ)$

Step	Hyp	Ref	Expression
1		expimpd.1	$⊢ (φ \land ψ) \to (χ \to θ)$
2	1	ex	$⊢ φ \to (ψ \to (χ \to θ))$
3	2	impd	$⊢ φ \to ((ψ \land χ) \to θ)$