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Metamath Proof Explorer

Theorem expcomd

Description: Deduction form of expcom . (Contributed by Alan Sare, 22-Jul-2012)

		Ref	Expression
	Hypothesis	expcomd.1	$⊢ φ \to ((ψ \land χ) \to θ)$
	Assertion	expcomd	$⊢ φ \to (χ \to (ψ \to θ))$

Step	Hyp	Ref	Expression
1		expcomd.1	$⊢ φ \to ((ψ \land χ) \to θ)$
2	1	expd	$⊢ φ \to (ψ \to (χ \to θ))$
3	2	com23	$⊢ φ \to (χ \to (ψ \to θ))$