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Metamath Proof Explorer


Theorem equeuclr

Description: Commuted version of equeucl (equality is left-Euclidean). (Contributed by BJ, 12-Apr-2021)

Ref Expression
Assertion equeuclr x = z y = z y = x

Proof

Step Hyp Ref Expression
1 equtrr z = x y = z y = x
2 1 equcoms x = z y = z y = x