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Metamath Proof Explorer

Theorem disjrel

Description: Disjoint relation is a relation. (Contributed by Peter Mazsa, 15-Sep-2021)

		Ref	Expression
	Assertion	disjrel	$⊢ Disj R \to Rel R$

Step	Hyp	Ref	Expression
1		df-disjALTV	$⊢ Disj R \leftrightarrow (CnvRefRel ≀ R^{-1} \land Rel R)$
2	1	simprbi	$⊢ Disj R \to Rel R$