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Metamath Proof Explorer

Theorem disjimres

Description: Disjointness condition for restriction. (Contributed by Peter Mazsa, 27-Sep-2021)

Ref Expression
Assertion disjimres ⊢ Disj R → Disj R ↾ A

Proof

Step Hyp Ref Expression
1 resss ⊢ R ↾ A ⊆ R
2 1 disjssi ⊢ Disj R → Disj R ↾ A