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Metamath Proof Explorer


Theorem difxp1ss

Description: Difference law for Cartesian products. (Contributed by Thierry Arnoux, 24-Jul-2023)

Ref Expression
Assertion difxp1ss A C × B A × B

Proof

Step Hyp Ref Expression
1 difxp1 A C × B = A × B C × B
2 difss A × B C × B A × B
3 1 2 eqsstri A C × B A × B