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Metamath Proof Explorer

Theorem ancomd

Description: Commutation of conjuncts in consequent. (Contributed by Jeff Hankins, 14-Aug-2009)

		Ref	Expression
	Hypothesis	ancomd.1	$⊢ φ \to (ψ \land χ)$
	Assertion	ancomd	$⊢ φ \to (χ \land ψ)$

Step	Hyp	Ref	Expression
1		ancomd.1	$⊢ φ \to (ψ \land χ)$
2		ancom	$⊢ (ψ \land χ) \leftrightarrow (χ \land ψ)$
3	1 2	sylib	$⊢ φ \to (χ \land ψ)$