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Metamath Proof Explorer

Theorem 3coml

Description: Commutation in antecedent. Rotate left. (Contributed by NM, 28-Jan-1996)

		Ref	Expression
	Hypothesis	3exp.1	$⊢ (φ \land ψ \land χ) \to θ$
	Assertion	3coml	$⊢ (ψ \land χ \land φ) \to θ$

Step	Hyp	Ref	Expression
1		3exp.1	$⊢ (φ \land ψ \land χ) \to θ$
2	1	3com23	$⊢ (φ \land χ \land ψ) \to θ$
3	2	3com13	$⊢ (ψ \land χ \land φ) \to θ$