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Metamath Proof Explorer

Theorem recnd

Description: Deduction from real number to complex number. (Contributed by NM, 26-Oct-1999)

Ref Expression
Hypothesis recnd.1 
|- ( ph -> A e. RR )
Assertion recnd 
|- ( ph -> A e. CC )

Proof

Step Hyp Ref Expression
1 recnd.1 
 |-  ( ph -> A e. RR )
2 recn 
 |-  ( A e. RR -> A e. CC )
3 1 2 syl 
 |-  ( ph -> A e. CC )