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Description: The equality of two Hilbert lattice elements is determined by the atoms under them. ( chrelat4i analog.) (Contributed by NM, 24-May-2012)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | hlatle.b | |- B = ( Base ` K ) |
|
| hlatle.l | |- .<_ = ( le ` K ) |
||
| hlatle.a | |- A = ( Atoms ` K ) |
||
| Assertion | hlateq | |- ( ( K e. HL /\ X e. B /\ Y e. B ) -> ( A. p e. A ( p .<_ X <-> p .<_ Y ) <-> X = Y ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | hlatle.b | |- B = ( Base ` K ) |
|
| 2 | hlatle.l | |- .<_ = ( le ` K ) |
|
| 3 | hlatle.a | |- A = ( Atoms ` K ) |
|
| 4 | ralbiim | |- ( A. p e. A ( p .<_ X <-> p .<_ Y ) <-> ( A. p e. A ( p .<_ X -> p .<_ Y ) /\ A. p e. A ( p .<_ Y -> p .<_ X ) ) ) |
|
| 5 | 1 2 3 | hlatle | |- ( ( K e. HL /\ X e. B /\ Y e. B ) -> ( X .<_ Y <-> A. p e. A ( p .<_ X -> p .<_ Y ) ) ) |
| 6 | 1 2 3 | hlatle | |- ( ( K e. HL /\ Y e. B /\ X e. B ) -> ( Y .<_ X <-> A. p e. A ( p .<_ Y -> p .<_ X ) ) ) |
| 7 | 6 | 3com23 | |- ( ( K e. HL /\ X e. B /\ Y e. B ) -> ( Y .<_ X <-> A. p e. A ( p .<_ Y -> p .<_ X ) ) ) |
| 8 | 5 7 | anbi12d | |- ( ( K e. HL /\ X e. B /\ Y e. B ) -> ( ( X .<_ Y /\ Y .<_ X ) <-> ( A. p e. A ( p .<_ X -> p .<_ Y ) /\ A. p e. A ( p .<_ Y -> p .<_ X ) ) ) ) |
| 9 | 4 8 | bitr4id | |- ( ( K e. HL /\ X e. B /\ Y e. B ) -> ( A. p e. A ( p .<_ X <-> p .<_ Y ) <-> ( X .<_ Y /\ Y .<_ X ) ) ) |
| 10 | hllat | |- ( K e. HL -> K e. Lat ) |
|
| 11 | 1 2 | latasymb | |- ( ( K e. Lat /\ X e. B /\ Y e. B ) -> ( ( X .<_ Y /\ Y .<_ X ) <-> X = Y ) ) |
| 12 | 10 11 | syl3an1 | |- ( ( K e. HL /\ X e. B /\ Y e. B ) -> ( ( X .<_ Y /\ Y .<_ X ) <-> X = Y ) ) |
| 13 | 9 12 | bitrd | |- ( ( K e. HL /\ X e. B /\ Y e. B ) -> ( A. p e. A ( p .<_ X <-> p .<_ Y ) <-> X = Y ) ) |