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Metamath Proof Explorer


Theorem eqbrrdv2

Description: Other version of eqbrrdiv . (Contributed by Rodolfo Medina, 30-Sep-2010)

Ref Expression
Hypothesis eqbrrdv2.1
|- ( ( ( Rel A /\ Rel B ) /\ ph ) -> ( x A y <-> x B y ) )
Assertion eqbrrdv2
|- ( ( ( Rel A /\ Rel B ) /\ ph ) -> A = B )

Proof

Step Hyp Ref Expression
1 eqbrrdv2.1
 |-  ( ( ( Rel A /\ Rel B ) /\ ph ) -> ( x A y <-> x B y ) )
2 df-br
 |-  ( x A y <-> <. x , y >. e. A )
3 df-br
 |-  ( x B y <-> <. x , y >. e. B )
4 1 2 3 3bitr3g
 |-  ( ( ( Rel A /\ Rel B ) /\ ph ) -> ( <. x , y >. e. A <-> <. x , y >. e. B ) )
5 4 eqrelrdv2
 |-  ( ( ( Rel A /\ Rel B ) /\ ( ( Rel A /\ Rel B ) /\ ph ) ) -> A = B )
6 5 anabss5
 |-  ( ( ( Rel A /\ Rel B ) /\ ph ) -> A = B )