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Metamath Proof Explorer


Theorem bian1d

Description: Adding a superfluous conjunct in a biconditional. (Contributed by Thierry Arnoux, 26-Feb-2017) (Proof shortened by Hongxiu Chen, 29-Jun-2025) (Proof shortened by Peter Mazsa, 24-Feb-2026)

Ref Expression
Hypothesis bian1d.1
|- ( ph -> ( ps <-> ( ch /\ th ) ) )
Assertion bian1d
|- ( ph -> ( ( ch /\ ps ) <-> ( ch /\ th ) ) )

Proof

Step Hyp Ref Expression
1 bian1d.1
 |-  ( ph -> ( ps <-> ( ch /\ th ) ) )
2 1 baibd
 |-  ( ( ph /\ ch ) -> ( ps <-> th ) )
3 2 pm5.32da
 |-  ( ph -> ( ( ch /\ ps ) <-> ( ch /\ th ) ) )